Rule of thumbs in Reservoir Engineering
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Rule of thumbs in Reservoir Engineering
Hello members,
Long time ago we didn't get in touch together. This thread is interactive and will need your cooperation.
All practical aspects in Reservoir Engineering will be listed here......
Let us start
Long time ago we didn't get in touch together. This thread is interactive and will need your cooperation.
All practical aspects in Reservoir Engineering will be listed here......
Let us start
What is the minimum core size required for SCAL
Normally, the Core is cutting size is less than the Wellbore (hole size).
For example, If you drill 7" hole so the expected core size will be 5-6".
For running SCAL so you need at least 2" plug length which is perpendicular on the axis of the main core.
At least 2/3 of Core diameter will be used for core plug which 2/3 * 6 = 4"
Generally, the core size (Diameter) of 5" is the minimum for applying SCAL .
For example, If you drill 7" hole so the expected core size will be 5-6".
For running SCAL so you need at least 2" plug length which is perpendicular on the axis of the main core.
At least 2/3 of Core diameter will be used for core plug which 2/3 * 6 = 4"
Generally, the core size (Diameter) of 5" is the minimum for applying SCAL .
Re: Rule of thumbs in Reservoir Engineering
Very good idea.
In deep-water plays and in order to calculate the reservoir temperature (if you don't have actual data):
Consider the seabed temperature is 4 dec C (rule of thumb) for any ocean or sea unless you have real data.
start counting from seabed downward to the reservoir .i.e. subtract the water depth from the total depth in -MSS and apply the regional geothermal gradient.
Example:
If you have a well targeting reservoir A with depth of 4000 meter SS
And water depth of 1500 meter
and the geothermal gradient is 5 C/100 meter
Then 4000 - 1500 = 2500 meter (depth from seabed to reservoir A)
2500 * 5/100 = 125 C (incremental of temp.)
So, the temperature at on A depth = 125+4 = 129 C.
In deep-water plays and in order to calculate the reservoir temperature (if you don't have actual data):
Consider the seabed temperature is 4 dec C (rule of thumb) for any ocean or sea unless you have real data.
start counting from seabed downward to the reservoir .i.e. subtract the water depth from the total depth in -MSS and apply the regional geothermal gradient.
Example:
If you have a well targeting reservoir A with depth of 4000 meter SS
And water depth of 1500 meter
and the geothermal gradient is 5 C/100 meter
Then 4000 - 1500 = 2500 meter (depth from seabed to reservoir A)
2500 * 5/100 = 125 C (incremental of temp.)
So, the temperature at on A depth = 125+4 = 129 C.